SOLUTION: how many liters of a 20% dye solution and a 50% solution should be mixed to obtain 6 liters of a 40% solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many liters of a 20% dye solution and a 50% solution should be mixed to obtain 6 liters of a 40% solution      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 353860: how many liters of a 20% dye solution and a 50% solution should be mixed to obtain 6 liters of a 40% solution
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
Let x be the amount of the 50% total solution. then (6L-x) would be the amount of the 20% total solutiom
.
question states
.50x + .20(6L-x)=.40*6L
.
simplify and solve
.30x = .40*6L - .20*6L
.
x (the amount of the 50% total solution)= 4L
the amount of the 20% total solution = 2L