Question 353772: find four consecutive even numbers such that three-fourths of the sum of the second and fourth numbers equals the sum of the first and the third numbers.
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! x, x+2,x+4,x+6 be the numbers
...
3/4 of the sum of second and fourth = 3/4 ( x+2+x+6)
sum of first & third = x+x+4
...
3/4(2x+8)=2x+4
3(2x+8)=4(2x+4)
6x+24=8x+16
8x-6x=24-16
2x=8
x= 4...
numbers are 4,6,8,10
.....
m.ananth@hotmail.ca
|
|
|