SOLUTION: Solve each radical equation. Check your solution. If there is no solution, whrite no solution. These were the directions in the text book and this is the equation: {{{ x+3= sq

Algebra ->  Radicals -> SOLUTION: Solve each radical equation. Check your solution. If there is no solution, whrite no solution. These were the directions in the text book and this is the equation: {{{ x+3= sq      Log On


   



Question 35339This question is from textbook Prentice Hall Algebra 1
: Solve each radical equation. Check your solution. If there is no solution, whrite no solution.
These were the directions in the text book and this is the equation:
+x%2B3=+sqrt%28x%5E2-4x-1%29+
first i squared the whole thing to get +x%5E2%2B9=x%5E2-4x-1+ but i dont know what to do after that. Can you please help?
Thank you very much for your time and effort.
This question is from textbook Prentice Hall Algebra 1

Answer by narayaba(40) About Me  (Show Source):
You can put this solution on YOUR website!
x+3 = sqrt(x^2-4x-1)
squaring both sides
(x+3)^2 = x^2 -4x - 1
using the identity (a+b)^2 = a^2 +2*a*b + b^2
x^2 + 6x + 9 = x^2 -4x -1
10x = -10
x = -1