SOLUTION: solve for x:lne^2x+1=9

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Question 353339: solve for x:lne^2x+1=9
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
ln%28e%5E2x%29%2B1=9
If this is not your problem, please put parentheses around function arguments.

There are several ways we could solve for x. One way would be to take advantage of the fact that e, which is in the argument, is the base of natural logs (ln). We can use the property of logarithms, log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29, to move the exponent in the argument out in front:
2x%2Aln%28e%29%2B1=9
By definition, ln(e) = 1 so this becomes:
2x + 1 = 9
This is easy to solve for x:
2x = 8
x = 4