Question 353221: find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function
f(x)=1/2(x+3)^2+3? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function
f(x)=1/2(x+3)^2+3?
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Your equation IS in vertex form:
y = a(x-h)^2+k
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The vertex is (h,k)
-h = 3
h = -3
k = 3
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Vertex is (-3,3)
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Since the coefficient of (x+3) is positive
the parabola opens UP.
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The line of symmetry is a vertical line passing
through the vertex.
Therefore its equation is x = -3
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Cheers,
Stan H.
Therefore the vertex is at a minimum point.
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