SOLUTION: graph the inequality on a plane 3x+4y greater or equal to 12

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Question 353163: graph the inequality on a plane
3x+4y greater or equal to 12
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
3x+%2B+4y+%3E=+12
+4y+%3E=+-3x+%2B+12
+y+%3E=+%28-3%2F4%29x+%2B+3
.
Note: y = (-3/4)x + 3 represent the graph of a line with a slope of (-3/4) and y-intercept = 3.
Pt(0,3) and for ex. Pt(4, 0)are on the line
.
Graphing the >= inequality: shade the area above the line, noting the line is to be included.
graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%28-3%2F4%29x%2B3%29%29