SOLUTION: Graph the system of linear inequalities: x,<3; 2x+y>7
there is suppose to be a -under the < sign by the 3
please explain to me how you get the points to graph
thank you
april
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-> SOLUTION: Graph the system of linear inequalities: x,<3; 2x+y>7
there is suppose to be a -under the < sign by the 3
please explain to me how you get the points to graph
thank you
april
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Question 353122: Graph the system of linear inequalities: x,<3; 2x+y>7
there is suppose to be a -under the < sign by the 3
please explain to me how you get the points to graph
thank you
april Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Hi,
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The inequality describes all values of x that are less than or equal to three
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To graph, one would use a number line, a closed circle on a shaded arrow pointing to the left. (closed circle on 3 shows the 3 is included in the graph of the inequality )
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2x + y > 7
y>-2x + 7
*Note: if the > were an = sign, this would represent the equation of a line y = -2x + 7 with points (0,7) and ( 7/2, 0) on the line.
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As y is greater than -2x + 7, one would shaded the area above the line (the line itself is not included as being part of the graph of this 'inequality')
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