SOLUTION: Factor.
b^2+16b+64
I came up with (b+8)(b+8)
Factor completely.
81r^2-49
I came up with (9r+7)(9r-7)
Factor completely.
8x^4-64x^3+64x^2
I came up with 8x^2(x^2-8x+8)
F
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Factor.
b^2+16b+64
I came up with (b+8)(b+8)
Factor completely.
81r^2-49
I came up with (9r+7)(9r-7)
Factor completely.
8x^4-64x^3+64x^2
I came up with 8x^2(x^2-8x+8)
F
Log On
Question 353117: Factor.
b^2+16b+64
I came up with (b+8)(b+8)
Factor completely.
81r^2-49
I came up with (9r+7)(9r-7)
Factor completely.
8x^4-64x^3+64x^2
I came up with 8x^2(x^2-8x+8)
Factor completely.
4a^2+9-12a
I came up with (2a-3)^2
Solve.
x^2+2x-4=0
I came up with (x+2)(x-2)
Solve.
r^2-9r-10=0
I came up with (r-10)(r+1)
I am just looking for some direction on whether or not I have completed the above problems properly. When it comes to math, I always second guess myself. Any help you can give me to point me in the right direction is more than appreciated! Thank you so much in advance! Found 2 solutions by stanbon, Fombitz:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Factor.
b^2+16b+64
I came up with (b+8)(b+8)
Factor completely.
81r^2-49
I came up with (9r+7)(9r-7)
Factor completely.
8x^4-64x^3+64x^2
I came up with 8x^2(x^2-8x+8)
Factor completely.
4a^2+9-12a = 4a^2-12a+9
I came up with (2a-3)^2
Solve.
x^2+2x-4=0
[(x+4)(x-2)]
Solve.
r^2-9r-10=0
I came up with (r-10)(r+1)
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All good except next to last. I have bracked the correction.
=================
Cheers,
Stan H.
You can put this solution on YOUR website! You're almost there.
First, the easiest way to check to make sure is to work the problem forward and check if the factors give you back the original polynomial.
They did in all cases but the one below.
.
.
.
Yes,
Yes,
Yes,
Yes,
No,
Yes,
.
.
.
Second, if the problem to solve ?
or it it to factor ?
If you need to solve for the zeros then you need one more step for each problem.
(