SOLUTION: The point (1,2) has a distance _______ from the line defined by
Y= -X/3+1
(I think its the -x/3 fraction that messes me up)
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-> SOLUTION: The point (1,2) has a distance _______ from the line defined by
Y= -X/3+1
(I think its the -x/3 fraction that messes me up)
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Question 353079: The point (1,2) has a distance _______ from the line defined by
Y= -X/3+1
(I think its the -x/3 fraction that messes me up) Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! d = x1A +y1B +c / sqrt (A^2+B^2)
where A, B, C are the values of the equation Ax^2+Bx+C
y= -x/3 +1
y-1 = -x/3
3(y-1)=-x
3y-3=-x
x-3y-3 =0
...
the point is (1,2)
1*1+2*-3+(-3) / sqrt 10
=-8/sqrt10
= -8/3.16
-2.53
you have to take the modulus of the answer. so distance = 2.53
...
m.ananth@hotmail.ca
