SOLUTION: please help me, im so confused!
Solve 5^(sin2x) = 3.307
if i wasnt clear sin2x is the exponent of 5. we're learning about logarithms and natural logs and stuff, i just dont g
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Exponential-and-logarithmic-functions
-> SOLUTION: please help me, im so confused!
Solve 5^(sin2x) = 3.307
if i wasnt clear sin2x is the exponent of 5. we're learning about logarithms and natural logs and stuff, i just dont g
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Question 35303: please help me, im so confused!
Solve 5^(sin2x) = 3.307
if i wasnt clear sin2x is the exponent of 5. we're learning about logarithms and natural logs and stuff, i just dont get it! Answer by longjonsilver(2297) (Show Source):
Take logs to base5: i shall just write the word "log" without a subscript.
Now, the reason for taking logs to base 5 is that log to base 5 of (5) is 1. So:
Now, what the hell is log-base5 of (3.307)...your calculator doesn't store base5 logs. It does store base10 though, so we are going to convert the base5 into a base10. Pretty straightforward really:
--> here the 2 logs are now both base10. Work the right hand side out on your calculator to give:
sin2x = 0.743142 to 6dp
so, now need to solve this trig equation. What is the domain of x? Since sin is a repeating function, you will have an infinite number of solutions, as it stands.
I shall do the "obvious" one:
2x = sin^(-1)(0.743142)
2x = whatever
x = whatever/2
--> i do not have a calculator handy to find this angle for you.