SOLUTION: Find a linear equation that is perpendicular to the linear equation 2x-5y=3. I don't know how to do this without given points.

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Question 352703: Find a linear equation that is perpendicular to the linear equation 2x-5y=3.
I don't know how to do this without given points.
Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find a linear equation that is perpendicular to the linear equation 2x-5y=3.
I don't know how to do this without given points.
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Find the slope of the given line: m1 = 2/5
The slope of lines perpendicular is the negative inverse, = -5/2
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y = (-5/2)x + k is a line perpendicular.
k can be any number.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to slope-intercept form, y=mx%2Bb
2x-5y=3
5y=2x-3
y=%282%2F5%29x-3%2F5
Perpendicular lines have slopes that are negative reciprocals,
m%5B1%5D%2Am%5B2%5D=-1
%282%2F5%29%2Am%7B2%5D=-1
m%5B2%5D=-5%2F2
The perpendicular line has the equation,
y=-%285%2F2%29x%2Bb
You are free to to choose any value for b.
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Here is the original line and three perpendicular lines for values of b=0, b=6, and b=-6.
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