SOLUTION: the expression 16t^2 models the distance in feet that an object falls during t seconds after being dropped find the distance an object falls during each time
o.25 seconds 0.5
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o.25 seconds 0.5
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Question 352590: the expression 16t^2 models the distance in feet that an object falls during t seconds after being dropped find the distance an object falls during each time
o.25 seconds 0.5 seconds 2 seconds 10 seconds Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! the expression 16t^2 models the distance in feet that an object falls during t seconds after being dropped find the distance an object falls during each time
.
Just "plug in the values":
o.25 seconds:
16t^2 = 16(0.25)^2 = 16(0.0625) = 1 feet
.
0.5 seconds:
16t^2 = 16(0.5)^2 = 16(0.25) = 4 feet
.
2 seconds:
16t^2 = 16(2)^2 = 16(4) = 64 feet
.
10 seconds:
16t^2 = 16(10)^2 = 16(100) = 1600 feet
