SOLUTION: A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the
Log On
Question 352570: A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A radiator contains 25 quarts of water and anti-freeze solution, of which 60% (by volume) is anti-freeze. How much of this solution must be drained and replaced with water for the new solution to be 40% anti-freeze?
-----------------------
Equation:
water -water + water = water
0.40*25 - 0.40x + 1.00x = 0.60*25
-----
Multiply thru by 100 to get:
40*25 + 40x + 100x = 60*25
140x = 20*25
x = (1/7)25
x = 3.57 quarts of the original mix must be replaced
============================
Cheers,
Stan H.
(