SOLUTION: the length of a rectangle is 17 feet less than 4 times the width. the perimeter is 196 feet. find the width (in feet) Could you please show me the steps like how you did it? P

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the length of a rectangle is 17 feet less than 4 times the width. the perimeter is 196 feet. find the width (in feet) Could you please show me the steps like how you did it? P      Log On


   

Question 352525: the length of a rectangle is 17 feet less than 4 times the width. the perimeter is 196 feet. find the width (in feet)

Could you please show me the steps like how you did it? PLEASE
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter P = 2L + 2W = 196, from the given. Thus
L+%2B+W+=+98. (After dividing both sides by 2.)
Also from the given,
L+=+4%2AW+-+17.
Hence, by direct substitution,
4%2AW+-+17+%2B+W+=+98,
5%2AW+=+98+%2B+17+=+115,
W+=+115%2F5+=+23.
Therefore, the width is 23 feet and the lenth is 4%2A23+-+17+=+75+feet.