SOLUTION: please help me find b^2 - 4ac and the number of real solutions to the equation below -2x^2 + 5x - 6 = 0

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Question 35217: please help me find b^2 - 4ac and the number of real solutions to the equation below
-2x^2 + 5x - 6 = 0
Found 2 solutions by venugopalramana, longjonsilver:
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
please help me find b^2 - 4ac and the number of real solutions to the equation below
-2x^2 + 5x - 6 = 0...........AX^2+BX+C=0..IS THE STD.EQN.COMPARING...
A=-2...B=5...........C=-6
B^2-4AC=5^2-4*(-2)*(-6)=25-48=-23=NEGATIVE...HENCE THERE ARE NO REAL ROOTS FOR THIS EQN.

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
a=-2
b=5
c=-6

+b%5E2+-+4ac+
+%285%29%5E2+-+4%28-2%29%28-6%29+
+25+-+4%2812%29+
+25+-+48+
answer is negative so there are no real solutions.

jon.