SOLUTION: A ship using sound-sensing devices above and below water recorded a surface explosion 39 seconds sooner on its underwater device than on its above-water device. If sound travels in
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Question 352113: A ship using sound-sensing devices above and below water recorded a surface explosion 39 seconds sooner on its underwater device than on its above-water device. If sound travels in air at about 1,100 feet per second and in water at about 5,000 feet per second, how har away was the explosion? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A ship using sound-sensing devices above and below water recorded a surface
explosion 39 seconds sooner on its underwater device than on its above-water
device.
If sound travels in air at about 1,100 feet per second and in water at about
5,000 feet per second, how far away was the explosion?
:
let d = distance to the explosion
:
Write a time equation: time = dist/speed
: - = 39
Multiply equation by 55000, to clear the denominators, results
50d - 11d = 55000(39)
39d = 55000(39)
divide both sides by 39
d = 55000 ft
:
:
Check solution by finding the actual times - =
50 - 11 = 39
