SOLUTION: Solve the differential equation 1/y^2 y' =2x Find the special solution which satisfies the condition y(0)=1 PLLLSSS I NEED IT NOW :( THANKS YOUUU!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve the differential equation 1/y^2 y' =2x Find the special solution which satisfies the condition y(0)=1 PLLLSSS I NEED IT NOW :( THANKS YOUUU!      Log On


   

Question 352078: Solve the differential equation 1/y^2 y' =2x Find the special solution which satisfies the condition y(0)=1 PLLLSSS I NEED IT NOW :( THANKS YOUUU!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Oh well if you need it now.
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dy%2Fy%5E2=2xdx
Integrate both sides.
int%28%281%2Fy%5E2%29%2Cdy%29=int%28%282x%29%2Cdx%29
-y%5E%28-1%29=x%5E2
-1%2Fy=x%5E2%2BC
Use the initial condition to solve for C.
-1%2Fy=x%5E2%2BC
-1%2F1=0%5E2%2BC
C=-1
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-1%2Fy=x%5E2%2B1
y=-1%2F%28x%5E2%2B1%29