SOLUTION: Find the value of k so that (k+2)x-3y=1 has slope 2 I've been stuck in this problem. I check other problems that has the same setting but still don't get it. If you guys coul

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Question 352008: Find the value of k so that (k+2)x-3y=1 has slope 2
I've been stuck in this problem. I check other problems that has the same setting but still don't get it.
If you guys could help me I'll be really thankful.
Thanks
Found 2 solutions by scott8148, solver91311:
Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website!
the slope-intercept form of a line is ___ y = mx + b ___ m is the slope , b is the y-intercept

subtracting (k+2)x ___ -3y = -(k+2)x + 1

dividing by -3 ___ y = [(k+2) / 3]x - 1/3

for this case ___ (k+2) / 3 = 2 ___ k + 2 = 6 ___ k = 4

Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

Consider the binomial expression on to be nothing more than a coefficient like any other. Put the equation in slope-intercept form.

Add to both sides:

Multiply both sides by

Now the coefficient on is the slope. But you were given that the slope is 2, so:

Solve for

John

My calculator said it, I believe it, that settles it