SOLUTION: In a triangle, angle A is 1/3 of angle B and angle C is 40 degree more than angle B. Find the measure of each angle.

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Question 351939: In a triangle, angle A is 1/3 of angle B and angle C is 40 degree more than angle B. Find the measure of each angle.
Answer by stanbon(75887) About Me  (Show Source):
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In a triangle, angle A is 1/3 of angle B and angle C is 40 degree more than angle B. Find the measure of each angle.
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Equations:
A + B + C = 180
B = 3A
C = B + 40
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A+B+C = 180
B = 3A
C = 3A + 40
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Substitute and solve for A:
A + 3A + 3A+40 = 180
7A = 140
A = 20 degrees
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B = 3A = 60 degrees
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C = 3A+40 = 100 degrees
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cheers,
Stan H.