SOLUTION: Problem goes like this..... Solve equation. log (x+5) - log (x-1) = log (x+2) - log (x-3)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Problem goes like this..... Solve equation. log (x+5) - log (x-1) = log (x+2) - log (x-3)      Log On


   

Question 35192: Problem goes like this.....
Solve equation.
log (x+5) - log (x-1) = log (x+2) - log (x-3)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log (x+5) - log (x-1) = log (x+2) - log (x-3)
log[(x+5)/(x-1)] = log[(x+2)/(x-3)]
Take the anti-log of both sides to get:
[(x+5)/(x-1)] = [(x+2)/(x-3)]
Cross-multiply to get:
x^2+2x-15= x^2+x-2
x=13
Check the answer in the original equation; it works.
Cheers,
Stan H.