SOLUTION: solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60-gallon mixture that is 50% acid? please write the representation of
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Question 351633: solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60-gallon mixture that is 50% acid? please write the representation of this problem. Found 2 solutions by ewatrrr, Alan3354:Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Hi,
Let x be the 'total' amount of the 30% solution. then the 'total' amount of the 60% solution would be (60gal - x)
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Question states;
.30x + .60(60gal - x) = .50*60gal
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Solve for x and then determine the value (60gal- x),as well.
You can put this solution on YOUR website! t = amount of 30%
s = amount of 60%
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t + s = 60 (total solution)
0.3t + 0.6s = 0.5*60 (acid)
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2 eqns in 2 unknowns. You can finish it
