SOLUTION: When i worked this problem, the graph did not turn out right. The equation is xsquared-5x+6=0. I have to solve the equation by graphing. could you please help me out?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: When i worked this problem, the graph did not turn out right. The equation is xsquared-5x+6=0. I have to solve the equation by graphing. could you please help me out?      Log On


   

Question 35155This question is from textbook Algebra 1
: When i worked this problem, the graph did not turn out right. The equation is xsquared-5x+6=0. I have to solve the equation by graphing. could you please help me out? This question is from textbook Algebra 1

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Graph y+=+x%5E2+-5x+%2B6, and see where the graph crosses the x-axis. These points will be the solutions of the equation.

+graph+%28300%2C300%2C-4%2C6%2C-4%2C8%2C+x%5E2-5x%2B6+%29+

As you can see, the graph crosses the x-axis at x= 2 and x=3. These are the solutions of the equation.

R^2 at SCC