SOLUTION: The sum of two numbers are 72. Their difference is 48. Find the numbers.
so far i did , let x represent the first number
let y represent the second number.
x+y=78
x-y=48
Question 351174: The sum of two numbers are 72. Their difference is 48. Find the numbers.
so far i did , let x represent the first number
let y represent the second number.
x+y=78
x-y=48
now i have to solve it but i don't know if i did.
thank you for helping. Found 2 solutions by ewatrrr, stanbon:Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Hi, your on the righ track.
*Note: sum of the numbers is "72" , difference 48
.
x+y=72
y = 72-x
.
x-y =48
.
Substitute for y
x -(72-x) =48
Simplify and solve
x - 72 +x = 48
2x = 120
.
x = 60
y = 72 -60 = 12
.
check your answer
60-12 = 48
You can put this solution on YOUR website! x+y=78
x-y=48
----
Add and solve for "x":
2x = 126
x = 63
----
Since x+y = 78 , y = 15
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Cheers,
Stan H.
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