SOLUTION: Find three consecutive integers such that twice the least integer is 12 more than the greatest integer. Thanks for your help!
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Question 351065
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Find three consecutive integers such that twice the least integer is 12 more than the greatest integer. Thanks for your help!
Answer by
nyc_function(2741)
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You can
put this solution on YOUR website!
2x = (x + 2) + 12
Can you finish?
HINT: The three consecutive integers are x, x + 1 and x + 2 but you need to
find x first.
Undersand?