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| Question 351025:  Marks: 1
 Find the equation passing through the given y-intercept with the given slope.
 (0, -6), m = -3
 Choose one answer.
 A. y = –6x – 3
 B. –6x – 3y = 0
 C. y = –3x – 6
 D. –3y = –6
 Find the equation passing through the given point with the given slope.
 
 (4, -17), m = -2
 Choose one answer.
 A. y = -2x – 9
 B. y = -2x – 17
 C. -2x + 4y = -17
 D. 4x – 2y = -9
 Marks: 1
 Find the slope and the y-intercept for the following equation.
 
 3x + 2y = 6
 Choose one answer.
 A. m = -3/2, b = -3
 B. m = -3/2, b = 3
 C. m =3/2, b= -3
 D. m =3/2, b=3
 Marks: 1
 Find the slope and the y-intercept for the following equation.
 
 x - 3y = 9
 Choose one answer.
 A. m = -1/3, b = -3
 B. m = -1/3, b = 3
 C. m =1/3, b= -3
 D. m =1/3, b=3
 Find the x-intercept and the y-intercept for the following equation
 
 5x – 2y = -10
 Choose one answer.
 A. (0, 5 ); ( -2, 0)
 B. (0,-5 ); (2 , 0)
 C. (0, -2 ) (5, 0)
 D. (0,2 ); (-5, 0)
 Find the x-intercept and the y-intercept for the following equation
 
 3x + 7y = -21
 Choose one answer.
 A. (0, 7 ); ( -3, 0)
 B. (0,-7 ); (-3 , 0)
 C. (0, -7 ) (3, 0)
 D. (0,-3 ); (-7, 0)
 Marks: 1
 Write an equation for the line passing through the following given points.
 
 (-2, 6), (3,1)
 Choose one answer.
 A. y = -3x + 4
 B. y = x – 4
 C. y = -x + 4
 D. y = 5x + 4
 Marks: 1
 Write an equation for the line passing through the following given points.
 
 (-3, 4), (-2,1)
 Choose one answer.
 A. y = -3x - 5
 B. y = 1/3x – 5
 C. y = -1/3x + 5
 D. y = 3x + 5
 Write an equation for the line passing through the following given points.
 
 (0, 2), (1, ¾)
 Choose one answer.
 A. y = -4/5x + 2
 B. y = 4/5x – 2
 C. y = -5/4x + 2
 D. y = 5/4x -2
 
 Marks: 1
 Write an equation for the line parallel to the line 6x + 3y = -8 through the origin.
 Choose one answer.
 A. y = -2x +0
 B. y =2x +0
 C. y = -1/2x +0
 D. y = 1/2x +0
 
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! Do them like these: Given 2 points example.
 Find the equation of the line thru the points (2,1) and (3,5)
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 This is a 2 step process.  First find the slope of the line thru the points.
 slope, m = diffy/diffx
 m = (5-1)/(3-2)
 m = 4
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 Now use y = mx + b with either point to find b, the y-intercept.
 y = mx + b
 5 = 4*3 + b
 b = -7
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 y = mx + b
 y = 4x - 7 is the answer.
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 Another approach using determinants:
 |x y 1|
 |2 1 1| = 0
 |3 5 1|
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 x(1-5) - y(2-3) + 1(10-3) = 0
 -4x + y + 7 = 0
 y = 4x - 7
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 For further assistance, or to check your work, email me via the thank you note
 or at Moral Loophole@aol.com
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 A line and a point example.
 Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
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 Find the slope of the line.  Do that by putting the equation in slope-intercept form, y = mx + b.  That means solve for y.
 9x+3y = 36
 3y= - 9x + 36
 y = -3x + 12
 The slope, m = -3
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 The slope of lines parallel is the same.
 The slope of lines perpendicular is the negative inverse, m = +1/3
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 Use y = mx + b and the point (1,2) to find b.
 2 = (1/3)*1 + b
 b = 5/3
 The equation is y = (1/3)x + 5/3 (slope-intercept form)
 x - 3y = -5 (standard form)
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 For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
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