SOLUTION: Find the points on the curve y = 2x^3 + 3x^2 -12x +1 where the tangent line is horizontal

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Question 350595: Find the points on the curve y = 2x^3 + 3x^2 -12x +1 where the tangent line is horizontal
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
y=2x%5E3%2B3x%5E2-12x%2B1
The slope of the tangent line is the value of the derivative.
Horizontal lines have a slope of m=0
Find x when,
m=dy%2Fdx=6x%5E2%2B6x-12=0
x%5E2%2Bx-2=0
%28x%2B2%29%28x-1%29=0
Two solutions:
x%2B2=0
highlight%28x=-2%29
.
.
x-1=0
highlight%28x=1%29
.
.
.