SOLUTION: suppose A is a 3x3 matrix with elements
a11 =1 a12=0 a13=2
a21=-1 a22=3 a23=4
a31=0 a32=1 a33=0
how would you use A^-1 to find the solutions of the linear system
x+2z = 1 and
Algebra ->
Matrices-and-determiminant
-> SOLUTION: suppose A is a 3x3 matrix with elements
a11 =1 a12=0 a13=2
a21=-1 a22=3 a23=4
a31=0 a32=1 a33=0
how would you use A^-1 to find the solutions of the linear system
x+2z = 1 and
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Question 350586: suppose A is a 3x3 matrix with elements
a11 =1 a12=0 a13=2
a21=-1 a22=3 a23=4
a31=0 a32=1 a33=0
how would you use A^-1 to find the solutions of the linear system
x+2z = 1 and -x+3y+4z =2 and y=3
could you please show working.
i have used numbers with subscripts to depict the matrix entries because i dont know how to type the brackets Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! [A]=
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[A][x]=[b]
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where,
[x]=
[b]=
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[A][x]=[b]
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[A]inv[A][x]=[A]inv[b]
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Since [A]inv[A]=[I], then
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[x]=[A]inv[b]
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det[A]=
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[A]inv= *([A]inv[b])= *([A]inv[b])=
Then,
[x]=
