Question 350567: domain of h(x)=1/(x^(1/2)-5x)
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! Because the function has x^1/2 so -------> x is greater or equal to zero
And then we should make the "(x^1/2)-5x" equal to zero so the result is:
(x^1/2)-5x = 0 --------> x = 0 , 1/25
So the numbers "0 , 1/25" can't be in the domain.
So, the domain is: (0 , 1/25) U (1/25 , +infinity)
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