SOLUTION: <b> Solve using whatever counting methods are necessary. Please show work.</b> A box contains 5 red marbles and 7 black marbles. You draw 4 marbles randomly from the box. What i

Algebra ->  Probability-and-statistics -> SOLUTION: <b> Solve using whatever counting methods are necessary. Please show work.</b> A box contains 5 red marbles and 7 black marbles. You draw 4 marbles randomly from the box. What i      Log On


   



Question 35053: Solve using whatever counting methods are necessary. Please show work.
A box contains 5 red marbles and 7 black marbles. You draw 4 marbles randomly from the box. What is the probability that you will draw 3 red marbles and 1 black marble in any order?

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
4 options:
RRRB
RRBR
RBRR
BRRR

Look at RRRB ans assuming there is no replacement of marbles during this process:
First out is red: P = 5/12
second out is red: P = 4/11
third out is red: P = 3/10
fourth out is black: P = 7/9

--> P = +%285%2F12%29%2A%284%2F11%29%2A%283%2F10%29%2A%287%2F9%29+

Now look at RRBR:
--> P = +%285%2F12%29%2A%284%2F11%29%2A%287%2F10%29%2A%283%2F9%29+
which if you look closely is the same thing as RRRB

So, in total we have 4 versions of the same thing
--> P = 4+%285%2F12%29%2A%284%2F11%29%2A%283%2F10%29%2A%287%2F9%29+
--> P = +%284%2A5%2A4%2A3%2A7%29%2F%2812%2A11%2A10%2A9%29+
--> P = +%284%2A5%2A7%29%2F%2811%2A10%2A9%29+
--> P = +%284%2A7%29%2F%2811%2A2%2A9%29+
--> P = +%282%2A7%29%2F%2811%2A9%29+
--> P = +14%2F99+
--> P = 0.141414

jon.