SOLUTION: <b> Solve using whatever counting methods are necessary. Please show work.</b> How many 3 digit numbers are possible using 2, 3, 5, or 7 if you can repeat digits? Any help wo

Algebra ->  Probability-and-statistics -> SOLUTION: <b> Solve using whatever counting methods are necessary. Please show work.</b> How many 3 digit numbers are possible using 2, 3, 5, or 7 if you can repeat digits? Any help wo      Log On


   



Question 35052: Solve using whatever counting methods are necessary. Please show work.
How many 3 digit numbers are possible using 2, 3, 5, or 7 if you can repeat digits?
Any help would be greatly appreciated! Thank you!
Smiles!

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
i answered this yesterday. Have a look at my recent answers.
Answer is 24: 4*3*2
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Apologies, i did not read the question properly and assumed it was the same as before.

This is actually easier than the other example though.

With repetition we can have numbers like 222 or 353 etc.

First position: How many numbers are allowed there? Answer is 4
Second position: How many numbers are allowed there? Answer is again 4
Third position: How many numbers are allowed there? Answer is again 4

So in total we have 4*4*4 permutations --> 64.

Jon