SOLUTION: Please help me...i really do not understand how to solve for these answers. I have just tried plugging in different numbers and they were all wrong. I thought for sure that they wo
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-> SOLUTION: Please help me...i really do not understand how to solve for these answers. I have just tried plugging in different numbers and they were all wrong. I thought for sure that they wo
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Question 350166: Please help me...i really do not understand how to solve for these answers. I have just tried plugging in different numbers and they were all wrong. I thought for sure that they would be close to 0 but I can't seem to find anything that works.
Find two natural numbers a and b such that b > a and
a^b = b^a.
Then a = ___
and b=___
Hint: It is not usually true that a^b = b^a. Found 2 solutions by Alan3354, CharlesG2:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Please help me...i really do not understand how to solve for these answers. I have just tried plugging in different numbers and they were all wrong. I thought for sure that they would be close to 0 but I can't seem to find anything that works.
Find two natural numbers a and b such that b > a and
a^b = b^a.
Then a = ___
and b=___
Hint: It is not usually true that a^b = b^a.
natural numbers are the counting numbers 1,2,3,4,5,6,...
answer is a = 2, and b = 4
here b > a since 4 > 2
a^b = 2^4 = 16
b^a = 4^2 = 16
a^b = b^a = 16