SOLUTION: Graph the equation and idenify the y intercept. y=4x-3 I have unterstood for the most part i just am not understanding how they are getting the points for the variable x

Algebra ->  Graphs -> SOLUTION: Graph the equation and idenify the y intercept. y=4x-3 I have unterstood for the most part i just am not understanding how they are getting the points for the variable x      Log On


   

Question 350111: Graph the equation and idenify the y intercept.
y=4x-3
I have unterstood for the most part i just am not understanding how they are getting the points for the variable x
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x values are values you choose.
That's the independent variable.
Then once you choose that, the value of y is determined, it's the dependent variable (dependent on your choice of x).
The y-intercept is the value of y when x=0.
It's the value of the function when it crosses the y-axis.
y=4x-3
y=4%280%29-3
y=-3
(0,-3)
.
.
.
Choose any other x value and calculate y.
Then you'll have two points and you can draw your line.
How about x=2? Again, doesn't matter, it's your choice.
y=4x-3
y=4%282%29-3
y=8-3
y=5
(2,5)
.
.
.
Now plot the points and connect them with a line.
.
.
.