SOLUTION: please help me ma'am/sir!
here's the question. a man has 40 coins in nickels and dimes. what is the maximum number of dimes he should have to have more than $2.85?
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-> SOLUTION: please help me ma'am/sir!
here's the question. a man has 40 coins in nickels and dimes. what is the maximum number of dimes he should have to have more than $2.85?
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Question 350044: please help me ma'am/sir!
here's the question. a man has 40 coins in nickels and dimes. what is the maximum number of dimes he should have to have more than $2.85? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a man has 40 coins in nickels and dimes. what is the maximum number of dimes he should have to have more than $2.85?
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n + d = 40
5n + 10d = 285 cents
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Multiply thru the 1st equation by 5:
5n + 5d = 200
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Subtract that from the 2nd equation to get:
5d = 85
d = 17 (# of dimes needed to get $2.85 when you have 40 nickels and dimes)
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Cheers,
Stan H.
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