SOLUTION: Roger's age is 1 1/3 times Steven's age. Eight years ago, Roger's age was twice Steven's age. Find Roger's age.

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Question 349919: Roger's age is 1 1/3 times Steven's age. Eight years ago, Roger's age was twice Steven's age. Find Roger's age.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let steven's age be x
roger's age = 1 1/3 times stevens age.
=4/3 times = 4x/3
...
8 years ago
steven's age = x-8
roger's age = 4x/3 - 8
...
4x/3 -8 = 2(x-8)
(4x-24)/3 = 2x-16
x3
4x-24=3(2x-16)
4x-24=6x-48
6x-4x=48-24
2x=24
x=12 steven's age
Roger = 4/3 * 12
=16 years