SOLUTION: The length of a rectangle is 4 feet more three times its width. Find the largest possible width if the perimeter is no more than 80 feet.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The length of a rectangle is 4 feet more three times its width. Find the largest possible width if the perimeter is no more than 80 feet.      Log On


   

Question 349769: The length of a rectangle is 4 feet more three times its width. Find the largest possible width if the perimeter is no more than 80 feet.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=3W+4
2L+2W<=80
2(3W+4)+2W<=80
6W+8+2W<=80
8W<=80-8
8W<=72
W<=72/8
W<=9 ANS. FOR THE WIDTH.
L=3*9+4=27+4=31 ANS. FOR THE LENGTH.
PROOF:
2*31+2*9<=80
62+18<=80
80<=80