SOLUTION: 1300 x (1+.0925) to the 35th power

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Question 349662: 1300 x (1+.0925) to the 35th power
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can do this with logs:
1300%2A1.0925%5E35
Take the log. Note that the log of a product
is the sum of the logs of the factors
log%281300%29+%2B+35%2Alog%281.0925%29
log%2813%2A100%29+%2B+35%2Alog%281.0925%29
log%2813%29+%2B+log%28100%29+%2B+35%2Alog%281.0925%29
1.1139+%2B+2+%2B+35%2A.0384
3.1139+%2B+1.3448
4.4587
This is the log of the answer.
Now you have to find 10%5E4.4587
which is the antilog
10%5E4.4587+=+28754.1