Question 34939: Please help me with my over 200 to do, and confused on some of them. THIS ONE IS SO CONFSUING TO ME! a hard one!!!
Solve any way, but show work.
There are 15 books on the summer reading list. Three of them are plays, one is poetry, and the rest are novels. what is the probability that you will choose 2 novels and a play in that order if you choose the books a t random?
Answer by mbarugel(146)   (Show Source):
You can put this solution on YOUR website! Hello!
First of all, we know that there are 3 plays, 1 poetry and 11 novels (since there are 15 books).
Now, what's the probability of picking a novel in the first place? Since 11 out of the 15 books are novels, this probability is 11/15.
Given that we took the novel, now we have 14 books left, 10 of which are novels. The probability of drawing a novel now is then 10/14.
Finally, after you took the second novel, you're left with 13 books, 3 of which are plays. Therefore, the probability of picking a play in the 3rd place is 3/13.
We conclude that the probability of picking a novel, a novel and a play (in that order) is simply the product of the 3 probabilities:
So the probability you're looking for is 0.1208.
I hope this helps!
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