You can put this solution on YOUR website! a train a mile and a half long takes 1 minute and a half to go through a tunnel a mile and a half long. how fast is it going?
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distance the back of the train goes from the time the front enters
the tunnel to the time that the back exits the tunnel:
= 1.5 + 1.5 miles
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time to do that = 1 min = (1/60) hr.
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Equation:
rate = distance/time
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rate = 3 miles/(1/60) hr = 180 mph
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Note: If you just want the distance the front goes from the
time it enters the tunnel till the front exits the tunnel
the distance is 1.5 miles
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rate = 1.5(1/60) = 90 mph
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Cheers,
Stan H.
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