SOLUTION: in solving the equation log6(x-5)+log6(x-6)=1 a student correctly arrives at a step where x=8 or x=3. when these two values of x are verified? a.neither b.both c.only x=3 d.o

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: in solving the equation log6(x-5)+log6(x-6)=1 a student correctly arrives at a step where x=8 or x=3. when these two values of x are verified? a.neither b.both c.only x=3 d.o      Log On


   

Question 34919: in solving the equation log6(x-5)+log6(x-6)=1 a student correctly arrives at a step where x=8 or x=3. when these two values of x are verified?
a.neither
b.both
c.only x=3
d.only x=8
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
ONLY X=8...SINCE X=3 GIVES RAISE TO LOG OF NEGATIVE NUMBERS WHICH DO NOT EXIST.