SOLUTION: Assume that births are distributed evenly over the seven days of the week. If you ask 3 men to state the day of the week they were born, what is the probability that all three wer

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Question 349186: Assume that births are distributed evenly over the seven days of the week. If you ask 3 men to state the day of the week they were born, what is the probability that all three were born on a Wednesday?
I can not figure this out can some one help me and show me how to get the correct answer....
Thank you!
Found 2 solutions by vleith, stanbon:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
The probabilty for each day is the same. So there is a 1/7 chance of being born on Wednesday for EACH guy.
so, the odds that they are all born on a Wednesday is
1%2F7+%2A+1%2F7+%2A+1%2F7+=+1%2F343
The odds are 1 chance in 343 that all three are "Wednesday's child is full of woe,"

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Assume that births are distributed evenly over the seven days of the week. If you ask 3 men to state the day of the week they were born, what is the probability that all three were born on a Wednesday?
I can not figure this out can some one help me and show me how to get the correct answer....
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The birth days of individuals are independent.
P(one person born on Wed) = 1/7
P(two persons born on Wed) = (1/7)(1/7) = 1/49
P(three persons born on Wed) = (1/7)^3 = 0.0029
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Cheers,
Stan H.
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