SOLUTION: For moving purposes, the Hendersons bought 28 cardboard boxes for $234 . There were two kinds of boxes; the large ones cost $9.50 per box and the small ones were $7.50 per box. H

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: For moving purposes, the Hendersons bought 28 cardboard boxes for $234 . There were two kinds of boxes; the large ones cost $9.50 per box and the small ones were $7.50 per box. H      Log On


   

Question 349182: For moving purposes, the Hendersons bought 28 cardboard boxes for $234 . There were two kinds of boxes; the large ones cost $9.50 per box and the small ones were $7.50 per box. How many boxes of each kind did they buy?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let the two different sized boxes be represented by x and y. x is the larger box, y the smaller.
You are told
x+%2B+y+=+28
so x+=+28+-+y
9.5x+%2B+7.5y+=+234
9.5%2828-y%29+%2B+7.5y+=+234
266+-+9.5y+%2B+7.5y+=+234
-2y+=+-32
y+=+16
They bought 16 smaller boxes. To total 28 boxes, they must have 12 larger ones.