Question 349169: Pure acid is to be added to a 5% acid solution to obtain 95L if 80% solution. What amounts of each should be used? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let liters = amount of pure acid to be added
Let liters = amount of 5% solution needed
In words:
(total liters of acid in final solution)/(total liters of final solution)
= 80%
----------------------
given:
(1)
(2)
Multiply both sides of (1) by and
subtract from (2)
(2)
(1)
75 liters of pure acid and 20 liters of 5% acid solution are needed
check answer:
OK
