SOLUTION: Two cars leave a city and head in the same direction. After 7 hours, the faster car is 42 miles ahead of the slower car. The slower car has traveled 287 miles. Find the speeds of
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Question 349131: Two cars leave a city and head in the same direction. After 7 hours, the faster car is 42 miles ahead of the slower car. The slower car has traveled 287 miles. Find the speeds of the two cars. Answer by CharlesG2(834) (Show Source):
You can put this solution on YOUR website! Two cars leave a city and head in the same direction. After 7 hours, the faster car is 42 miles ahead of the slower car. The slower car has traveled 287 miles. Find the speeds of the two cars.
D distance = R rate * T time
287 miles + 42 miles = 329 miles
let R1 = speed of faster car
329 miles = R1 * 7 hours
329/7 = R1
47 mph = R1 = speed faster car
let R2 = speed of slower car
287 miles = R2 * 7 hours
287/7 = R2
41 mph = R2 = speed slower car
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