SOLUTION: A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 349130: A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed with 2 pounds of cherry candy to obtain a mixture that is priced at $10 per pound?
Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
A Store has decided to combine their peppermint candy, priced at $8 per pound, with their cherry candy, priced at $14 per pound. How many pounds of peppermint candy should be mixed with 2 pounds of cherry candy to obtain a mixture that is priced at $10 per pound?

amount A * price A + amount B * price B = amount C * price C
let A = peppermint candy, B = cherry candy, C = mixture of both
A + 2 = weight in pounds (lbs) of the mixture of candy
A * $8/lb + 2 lbs * $14/lb = (A + 2) lbs * $10/lb
8A + 28 = (A + 2) * 10
8A + 28 = 10A + 20
8A - 10A = 20 - 28
-2A = -8
2A = 8
A = 4 lbs peppermint candy