Question 34902: I would appreciate the kindness of your help. Thank you!
Use the fundamental counting principle to solve.
A company places a 6-symbol code on each unit of product. The code consists of 4 digits, the first of which is number 5, followed by two letters, the first of which is NOT a vowel. How many different codes are possible?
Found 2 solutions by stanbon, checkley71:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A company places a 6-symbol code on each unit of product. The code consists of 4 digits, the first of which is number 5, followed by two letters, the first of which is NOT a vowel. How many different codes are possible?
_ _ _ _ _ _
one way to do 1st digit; must be "5"
10 ways to pick a digit; any digit
10 ways to pick a digit; any digit
10 ways to pick a digit; any digit
21 ways to choose a letter; not a vowel
26 ways to choose a letter; any letter
# of codes = 1*10*10*10*21*26 = 546,000
Cheers,
Stan H.
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! FIRST DIGIT GIVEN = 1
THE NEXT 3 DIGITS CAN BE ANY ONE OF 10 10*10*10
FIRST LETTER, NOT A VOWEL, THUS WE HAVE 21 OPTIONS
SECOND LETTER - NO RESTRICTIONS, THUS 26 OPTIONS
SO WE HAVE 1*10*10*10*21*26=546,000 CODING COMBINATIONS.
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