SOLUTION: How do you set up the problem of "Find the dimensions of a rectangle whose width is 6 less than the legth" The perimeter is 56
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Question 348362: How do you set up the problem of "Find the dimensions of a rectangle whose width is 6 less than the legth" The perimeter is 56 Answer by Deja12347(3) (Show Source):
You can put this solution on YOUR website! 56= 2(w-6)+2w (Yes you use 2 w's. You subsitute l or length for another w.
56= 2w-12+2w (distributive property
56= 4w-12 ( combine like terms)
68=4w (add by 12 or do the opposite then divide by 4)
17=w
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