SOLUTION: Hello, I have tried to solve this problem! the problem reads: A movie theater has two ticket prices $8 for adults and $5 for kids. If the box office took in $4116. from the sale of
Algebra ->
Equations
-> SOLUTION: Hello, I have tried to solve this problem! the problem reads: A movie theater has two ticket prices $8 for adults and $5 for kids. If the box office took in $4116. from the sale of
Log On
Question 348347: Hello, I have tried to solve this problem! the problem reads: A movie theater has two ticket prices $8 for adults and $5 for kids. If the box office took in $4116. from the sale of 600 tickets, how many of each kind were sold? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A movie theater has two ticket prices $8 for adults and $5 for kids. If the box office took in $4116. from the sale of 600 tickets, how many of each kind were sold?
---------------------
Quantity: a + k = 600
Value: 8a+ 5k = 4116
--------------------------
5a + 5k = 3000
8a + 5k = 4116
----
Subtract the 1st from the 2nd and solve for "a":
3a = 1116
a = 372 (# of adult tickets sold)
----
Since a+k = 600, k = 228 (# of kids tickets sold)
=====================
Cheers,
stan H.
===============
(