SOLUTION: the length of a rectangle is 3 less than twice the width the perimeter of the rectangle is 78 find the dimensions of the rectangle

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Question 348130: the length of a rectangle is 3 less than twice the width the perimeter of the rectangle is 78 find the dimensions of the rectangle
Found 2 solutions by ovie27, london maths tutor:
Answer by ovie27(16) About Me  (Show Source):
You can put this solution on YOUR website!

Let:
x = length of the rectangle
y = width of the rectangle
x = 2y -3
perimeter = 2x + 2y = 78
Plug in x into the above equation:
2(2y-3) + 2y = 78
4y - 6 + 2y = 78
6y - 6 = 78
bring the 6 to the other side:
6y = 84
divide both sides by 6:
y = 14 = the width of the rectangle
The length is 2(14)-3 = 25
So, the length of the rectangle is 25 units, and the width is 14 units.

Answer by london maths tutor(243) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length be L and width be W and Perimeter be P
L = 2W-3
P = 78
By theory, P = 2L + 2W
Therefore,
78 = 2(2W-3) + 2W
78 = 4W - 6 + 2W
78 = 6W - 6
78 + 6 = 6W
84 = 6W
W = 84/6
W = 14
Therefore: L = 2(14)-3 = 25
Answer : Length = 25 and Width = 14
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