SOLUTION: 3 <= 4 + 3x/2 <= 2

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Question 347979: 3 <= 4 + 3x/2 <= 2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
In answer to your reply: choices being as follows for an answer to the "solution set":
a. {x|x > 2/3} b. {x|2/3 <= x <= 0} c. { } d. {x|x < 2/3}
.
Note: the results shown here indicated x+%3C=+-4%2F3 and x%3E=+-2%2F3
That is : x is to be all numbers to the left of -4/3 and all numbers to the right of -2/3.
The intersection of these graphs contains no numbers:
thus { } would be the correct response as to what is the 'solution set'
.
solving and determining the solution set are two separate steps.
The solution set of a compound inequality is always the Union of the two inequalties found to be true or the points they have in common. Hope this helps.

Hi,
*Note: a step at a time
3+%3C=+4+%2B+3x%2F2+%3C=+2
.
Take right side:
Subtract 4 from each side
3x%2F2+%3C=+-2
.
Multiply both sides of the two inequalities by 2/3
x%3C=+-4%2F3
.
Take left side: Solve
3+%3C=+4+%2B+3x%2F2
-1+%3C=+3x%2F2
-2%2F3+%3C=+x
.
combine
-2%2F3+%3C=+x%3C=-4%2F3