SOLUTION: a man is walking at an average speed of 4 miles per hour alongside a railroad track. a freight train, going in the same direction at an average speed of 30 miles per hour, requires
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: a man is walking at an average speed of 4 miles per hour alongside a railroad track. a freight train, going in the same direction at an average speed of 30 miles per hour, requires
Log On
Question 347975: a man is walking at an average speed of 4 miles per hour alongside a railroad track. a freight train, going in the same direction at an average speed of 30 miles per hour, requires 5 seconds to pass the man. how long is the freight train (in feet)? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a man is walking at an average speed of 4 miles per hour alongside a railroad track. a freight train, going in the same direction at an average speed of 30 miles per hour, requires 5 seconds to pass the man. how long is the freight train (in feet)?
---------------
The speed of the train relative to the man is 26 mph (30 - 4).
26 mph = 26*(22/15) ft/sec = 572/15 ft/sec
The length = = 572/15 ft/sec * 5 sec = 572/3 feet
= 190.67 feet